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National Institute of Technology, RourkelaFood Process Engineering

JEE (JOSAA) ST Cutoff 2025 · AI quota · Gender-Neutral

ST4 Years, B.TechOdisha

The National Institute of Technology, Rourkela Food Process Engineering cutoff for ST in 2025 was closing rank 2,685 (Round 6, OS quota).

2,685
Closing Rank
2,685
Opening Rank
Round 6
Round
ST
Category

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ST Cutoff Trend (20202025)

ST · last round of each year · hover for exact ranks

1.6K1.9K2.2K2.5K2.9K202020212022202320242025
Closing Rank
Opening Rank

ST Cutoffs 2025 — All Rounds

CategoryGenderQuotaOpening RankClosing Rank
STGender-NeutralOS2,6852,685
STGender-NeutralHS3,1823,182

ST Year-wise Closing Rank

YearRoundOpening RankClosing Rank
2025Round 62,6852,685
2024Round 52,1232,123
2023Round 62,2222,222
2022Round 62,2102,210
2021Round 61,7691,769
2020Round 62,1182,118

Food Process Engineering Cutoff — Other Categories

All JOSAA ST cutoffs →Food Process Engineering at all colleges →

Colleges Closing Near 2,685 for ST

Other JOSAA options with a similar ST closing rank in 2025.

Frequently Asked Questions

What is the ST cutoff for National Institute of Technology, Rourkela Food Process Engineering in JEE (JOSAA) 2025?

ST closing rank was 2,685 (Round 6, 2025). Opening rank was 2,685.

How many years of ST data is available?

JEE (JOSAA) ST cutoff for National Institute of Technology, Rourkela Food Process Engineering is available from 2020 to 2025.