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National Institute of Technology, RourkelaFood Process Engineering

JEE (JOSAA) SC Cutoff 2025 · AI quota · Gender-Neutral

SC4 Years, B.TechOdisha

The National Institute of Technology, Rourkela Food Process Engineering cutoff for SC in 2025 was closing rank 6,512 (Round 6, OS quota).

6,512
Closing Rank
6,512
Opening Rank
Round 6
Round
SC
Category

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SC Cutoff Trend (20202025)

SC · last round of each year · hover for exact ranks

3.9K5.1K6.3K7.5K8.7K202020212022202320242025
Closing Rank
Opening Rank

SC Cutoffs 2025 — All Rounds

CategoryGenderQuotaOpening RankClosing Rank
SCGender-NeutralOS6,5126,512
SCGender-NeutralHS9,0609,060
SCFemale-only (including Supernumerary)OS9,0979,097
SCFemale-only (including Supernumerary)HS13,30413,304

SC Year-wise Closing Rank

YearRoundOpening RankClosing Rank
2025Round 66,5126,512
2024Round 56,5256,525
2023Round 67,1857,646
2022Round 65,5266,198
2021Round 66,3208,100
2020Round 64,5566,370

Food Process Engineering Cutoff — Other Categories

All JOSAA SC cutoffs →Food Process Engineering at all colleges →

Colleges Closing Near 6,512 for SC

Other JOSAA options with a similar SC closing rank in 2025.

Frequently Asked Questions

What is the SC cutoff for National Institute of Technology, Rourkela Food Process Engineering in JEE (JOSAA) 2025?

SC closing rank was 6,512 (Round 6, 2025). Opening rank was 6,512.

How many years of SC data is available?

JEE (JOSAA) SC cutoff for National Institute of Technology, Rourkela Food Process Engineering is available from 2020 to 2025.