Indian Institute of Technology Roorkee — Applied Mathematics
JEE (JOSAA) ST Cutoff 2020 · AI quota · Gender-Neutral
ST5 Years, Integrated Master of ScienceUttarakhand
The Indian Institute of Technology Roorkee Applied Mathematics cutoff for ST in 2020 was closing rank 806 (Round 6, AI quota). This is the latest year with published JOSAA data.
806
Closing Rank
529
Opening Rank
Round 6
Round
ST
Category
Will you get Applied Mathematics at Indian Institute of Technology Roorkee in ST?
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Use JOSAA Predictor →ST Cutoffs 2020 — All Rounds
| Category | Gender | Quota | Opening Rank | Closing Rank |
|---|---|---|---|---|
| YOUR PICKST | Gender-Neutral | AI | 529 | 806 |
| ST | Female-only (including Supernumerary) | AI | 1,255 | 1,255 |
Applied Mathematics Cutoff — Other Categories
Colleges Closing Near 806 for ST
Other JOSAA options with a similar ST closing rank in 2020.
- IIT Guwahati — Civil Engineeringcloses 736
- IIT Bombay — Energy Engineering with M.Tech. in Energy Systems Engineeringcloses 735
- IIT Jodhpur — Materials Engineeringcloses 735
- IIT Gandhinagar — Mechanical Engineeringcloses 734
- IIT Kanpur — Chemical Engineeringcloses 733
- IIT Kharagpur — Economicscloses 726
- IIT Ropar — Mechanical Engineeringcloses 723
- IIT Goa — Electrical Engineeringcloses 722
- IIT (BHU) Varanasi — Civil Engineeringcloses 717
- NIT Karnataka, Surathkal — Electronics and Communication Engineeringcloses 717
Frequently Asked Questions
What is the ST cutoff for Indian Institute of Technology Roorkee Applied Mathematics in JEE (JOSAA) 2020?
ST closing rank was 806 (Round 6, 2020). Opening rank was 529.
How many years of ST data is available?
JEE (JOSAA) ST cutoff for Indian Institute of Technology Roorkee Applied Mathematics is available from 2020 to 2020.