Indian Institute of Technology Roorkee — Applied Mathematics
JEE (JOSAA) SC Cutoff 2020 · AI quota · Gender-Neutral
SC5 Years, Integrated Master of ScienceUttarakhand
The Indian Institute of Technology Roorkee Applied Mathematics cutoff for SC in 2020 was closing rank 1,237 (Round 6, AI quota). This is the latest year with published JOSAA data.
1,237
Closing Rank
561
Opening Rank
Round 6
Round
SC
Category
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Use JOSAA Predictor →SC Cutoffs 2020 — All Rounds
| Category | Gender | Quota | Opening Rank | Closing Rank |
|---|---|---|---|---|
| YOUR PICKSC | Gender-Neutral | AI | 561 | 1,237 |
| SC | Female-only (including Supernumerary) | AI | 1,890 | 1,890 |
Applied Mathematics Cutoff — Other Categories
Colleges Closing Near 1,237 for SC
Other JOSAA options with a similar SC closing rank in 2020.
- IIT Bombay — BS in Mathematicscloses 1,233
- IIT Indore — Mechanical Engineeringcloses 1,231
- IIT (BHU) Varanasi — Bioengineering with M.Tech in Biomedical Technologycloses 1,244
- IIT Guwahati — Mathematics and Computingcloses 1,229
- IIT Palakkad — Computer Science and Engineeringcloses 1,221
- IIT Ropar — Electrical Engineeringcloses 1,218
- IIT Gandhinagar — Electrical Engineeringcloses 1,213
- NIT Tiruchirappalli — Electrical and Electronics Engineeringcloses 1,213
- IIT Madras — Chemical Engineeringcloses 1,263
- IIT Madras — Mechanical Engineeringcloses 1,265
Frequently Asked Questions
What is the SC cutoff for Indian Institute of Technology Roorkee Applied Mathematics in JEE (JOSAA) 2020?
SC closing rank was 1,237 (Round 6, 2020). Opening rank was 561.
How many years of SC data is available?
JEE (JOSAA) SC cutoff for Indian Institute of Technology Roorkee Applied Mathematics is available from 2020 to 2020.