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CU JharkhandIntegrated B. Tech. - M. Tech in Electrical Engineering

JEE (JOSAA) OPEN (PwD) Cutoff 2024 · AI quota · Gender-Neutral

OPEN (PwD)5 Years, Integrated B. Tech. and M. Tech.Other

The CU Jharkhand Integrated B. Tech. - M. Tech in Electrical Engineering cutoff for OPEN (PwD) in 2024 was closing rank 4,335 (Round 5, AI quota). This is the latest year with published JOSAA data.

4,335
Closing Rank
4,335
Opening Rank
Round 5
Round
OPEN (PwD)
Category

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OPEN (PwD) Cutoffs 2024 — All Rounds

CategoryGenderQuotaOpening RankClosing Rank
YOUR PICKOPEN (PwD)Gender-NeutralAI4,3354,335

Integrated B. Tech. - M. Tech in Electrical Engineering Cutoff — Other Categories

All JOSAA OPEN (PwD) cutoffs →Integrated B. Tech. - M. Tech in Electrical Engineering at all colleges →

Colleges Closing Near 4,335 for OPEN (PwD)

Other JOSAA options with a similar OPEN (PwD) closing rank in 2024.

Frequently Asked Questions

What is the OPEN (PwD) cutoff for CU Jharkhand Integrated B. Tech. - M. Tech in Electrical Engineering in JEE (JOSAA) 2024?

OPEN (PwD) closing rank was 4,335 (Round 5, 2024). Opening rank was 4,335.

How many years of OPEN (PwD) data is available?

JEE (JOSAA) OPEN (PwD) cutoff for CU Jharkhand Integrated B. Tech. - M. Tech in Electrical Engineering is available from 2024 to 2024.