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CU JharkhandIntegrated B. Tech. - M. Tech in Electrical Engineering

JEE (JOSAA) OPEN Cutoff 2024 · AI quota · Gender-Neutral

OPEN5 Years, Integrated B. Tech. and M. Tech.Other

The CU Jharkhand Integrated B. Tech. - M. Tech in Electrical Engineering cutoff for OPEN in 2024 was closing rank 92,728 (Round 5, AI quota). This is the latest year with published JOSAA data.

92,728
Closing Rank
76,789
Opening Rank
Round 5
Round
OPEN
Category

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OPEN Cutoffs 2024 — All Rounds

CategoryGenderQuotaOpening RankClosing Rank
YOUR PICKOPENGender-NeutralAI76,78992,728

Integrated B. Tech. - M. Tech in Electrical Engineering Cutoff — Other Categories

All JOSAA OPEN cutoffs →Integrated B. Tech. - M. Tech in Electrical Engineering at all colleges →

Colleges Closing Near 92,728 for OPEN

Other JOSAA options with a similar OPEN closing rank in 2024.

Frequently Asked Questions

What is the OPEN cutoff for CU Jharkhand Integrated B. Tech. - M. Tech in Electrical Engineering in JEE (JOSAA) 2024?

OPEN closing rank was 92,728 (Round 5, 2024). Opening rank was 76,789.

How many years of OPEN data is available?

JEE (JOSAA) OPEN cutoff for CU Jharkhand Integrated B. Tech. - M. Tech in Electrical Engineering is available from 2024 to 2024.