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National Institute of Technology, RourkelaIndustrial Design

JEE (JOSAA) ST Cutoff 2025 · AI quota · Gender-Neutral

ST4 Years, B.TechOdisha

The National Institute of Technology, Rourkela Industrial Design cutoff for ST in 2025 was closing rank 1,930 (Round 6, OS quota).

1,930
Closing Rank
1,930
Opening Rank
Round 6
Round
ST
Category

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ST Cutoff Trend (20202025)

ST · last round of each year · hover for exact ranks

1.8K2.0K2.2K2.3K2.5K202020212022202320242025
Closing Rank
Opening Rank

ST Cutoffs 2025 — All Rounds

CategoryGenderQuotaOpening RankClosing Rank
STGender-NeutralOS1,9301,930
STGender-NeutralHS2,9842,984

ST Year-wise Closing Rank

YearRoundOpening RankClosing Rank
2025Round 61,9301,930
2024Round 52,3972,397
2023Round 62,0242,024
2022Round 61,9461,946
2021Round 62,1672,167
2020Round 62,3862,386

Industrial Design Cutoff — Other Categories

All JOSAA ST cutoffs →Industrial Design at all colleges →

Colleges Closing Near 1,930 for ST

Other JOSAA options with a similar ST closing rank in 2025.

Frequently Asked Questions

What is the ST cutoff for National Institute of Technology, Rourkela Industrial Design in JEE (JOSAA) 2025?

ST closing rank was 1,930 (Round 6, 2025). Opening rank was 1,930.

How many years of ST data is available?

JEE (JOSAA) ST cutoff for National Institute of Technology, Rourkela Industrial Design is available from 2020 to 2025.