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Indian Institute of Technology RoorkeeComputer Science and Engineering

JEE (JOSAA) ST Cutoff 2025 · AI quota · Gender-Neutral

ST4 Years, B.TechUttarakhand

The Indian Institute of Technology Roorkee Computer Science and Engineering cutoff for ST in 2025 was closing rank 77 (Round 6, AI quota).

77
Closing Rank
52
Opening Rank
Round 6
Round
ST
Category

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ST Cutoff Trend (20202025)

ST · last round of each year · hover for exact ranks

425466788202020212022202320242025
Closing Rank
Opening Rank

ST Cutoffs 2025 — All Rounds

CategoryGenderQuotaOpening RankClosing Rank
YOUR PICKSTGender-NeutralAI5277
STFemale-only (including Supernumerary)AI241258

ST Year-wise Closing Rank

YearRoundOpening RankClosing Rank
2025Round 65277
2024Round 55675
2023Round 64261
2022Round 61560
2021Round 62962
2020Round 65166

Computer Science and Engineering Cutoff — Other Categories

All JOSAA ST cutoffs →Computer Science and Engineering at all colleges →

Computer Science and Engineering ST Cutoff at Other Colleges

Same branch and category, ranked by 2025 closing rank.

Colleges Closing Near 77 for ST

Other JOSAA options with a similar ST closing rank in 2025.

Frequently Asked Questions

What is the ST cutoff for Indian Institute of Technology Roorkee Computer Science and Engineering in JEE (JOSAA) 2025?

ST closing rank was 77 (Round 6, 2025). Opening rank was 52.

How many years of ST data is available?

JEE (JOSAA) ST cutoff for Indian Institute of Technology Roorkee Computer Science and Engineering is available from 2020 to 2025.